The SO2 + OH -> H2SO4 reaction in CAM6

tomasz

New Member
Hi forum,
It's not clear to me how the reaction rate of SO2 (gas) + OH -> H2SO4 (gas) is calculated in CAM6. The equation report in chem_mech.doc gives this reaction as d(H2SO4)/dt = r3*OH*SO2. When looking through mo_usrrxt.F90 I find this expression for the reaction rate (rxt):

Code:
!-----------------------------------------------------------------
!       ... SO2 + OH  --> SO4  (REFERENCE?? - not Liao)
!-----------------------------------------------------------------
       if( usr_SO2_OH_ndx > 0 ) then
          fc(:) = 3.0e-31_r8 *(300._r8*tinv(:))**3.3_r8
          ko(:) = fc(:)*m(:,k)/(1._r8 + fc(:)*m(:,k)/1.5e-12_r8)
          rxt(:,k,usr_SO2_OH_ndx) = ko(:)*.6_r8**(1._r8 + (log10(fc(:)*m(:,k)/1.5e-12_r8))**2._r8)**(-1._r8)
       end if

which I think only depends on temperature (tinv) and atmospheric density (m). In mo_rxt_rates_conv.F90 it looks like the reaction rate is updated through

Code:
rxt_rates(:ncol,:,4) = rxt_rates(:ncol,:,4)*sol(:ncol,:,3)   ! rate_const*OH*SO2

I think sol(:,:,3) refers to the volumetric mixing ratio of SO2 but I'm not sure. I'm also not sure where the concentration of OH (which is prescribed in CAM6) is taken into account. Any clarifications would be greatly appreciated.

All the best, Tomas.
 
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