Scheduled Downtime
On Tuesday 24 October 2023 @ 5pm MT the forums will be in read only mode in preparation for the downtime. On Wednesday 25 October 2023 @ 5am MT, this website will be down for maintenance and expected to return online later in the morning.
Normal Operations
The forums are back online with normal operations. If you notice any issues or errors related to the forums, please reach out to help@ucar.edu

The SO2 + OH -> H2SO4 reaction in CAM6

tomasz

New Member
Hi forum,
It's not clear to me how the reaction rate of SO2 (gas) + OH -> H2SO4 (gas) is calculated in CAM6. The equation report in chem_mech.doc gives this reaction as d(H2SO4)/dt = r3*OH*SO2. When looking through mo_usrrxt.F90 I find this expression for the reaction rate (rxt):

Code:
!-----------------------------------------------------------------
!       ... SO2 + OH  --> SO4  (REFERENCE?? - not Liao)
!-----------------------------------------------------------------
       if( usr_SO2_OH_ndx > 0 ) then
          fc(:) = 3.0e-31_r8 *(300._r8*tinv(:))**3.3_r8
          ko(:) = fc(:)*m(:,k)/(1._r8 + fc(:)*m(:,k)/1.5e-12_r8)
          rxt(:,k,usr_SO2_OH_ndx) = ko(:)*.6_r8**(1._r8 + (log10(fc(:)*m(:,k)/1.5e-12_r8))**2._r8)**(-1._r8)
       end if

which I think only depends on temperature (tinv) and atmospheric density (m). In mo_rxt_rates_conv.F90 it looks like the reaction rate is updated through

Code:
rxt_rates(:ncol,:,4) = rxt_rates(:ncol,:,4)*sol(:ncol,:,3)   ! rate_const*OH*SO2

I think sol(:,:,3) refers to the volumetric mixing ratio of SO2 but I'm not sure. I'm also not sure where the concentration of OH (which is prescribed in CAM6) is taken into account. Any clarifications would be greatly appreciated.

All the best, Tomas.
 
Top